(1/6)^x=21

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Solution for (1/6)^x=21 equation: 



(1/6)^x=21

We move all terms to the left:

(1/6)^x-(21)=0



Domain of the equation: 6)^x!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

(+1/6)^x-21=0

We multiply all the terms by the denominator


(+1-21*6)^x=0

We add all the numbers together, and all the variables

(-125)^x=0

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